If it's not what You are looking for type in the equation solver your own equation and let us solve it.
h^2+3h+3=0
a = 1; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·1·3
Δ = -3
Delta is less than zero, so there is no solution for the equation
| 10x+23=-7-5x | | 4(x-3)+3=2x+2(-3+x | | 3y+2y=360 | | 18x-72=63-27x | | 9=-c/3 | | x/10=-19 | | 3(3x-6)+8x=14 | | 21s+6=189 | | 12.6=1+4k | | -1/8=7/4+3/2z | | 1=v-(-5) | | 10t=-44 | | -4(4x-5)=5x | | 19y+23=194 | | -4a+18+6a=3a-7a | | 5x-3.5=0.2x-0.5 | | 15.00p+0.20=75 | | 1000(9x-10=50(912+100x) | | 15.00p+8=7 | | 937/9=20/3(23/8x+11/5 | | 9t+1/7=t+8/14+t-6/14 | | x=0.09*(520757.73+x) | | 4x+3=-4+2x+17 | | 12d−14=13d+1 | | 22=8a | | X+0.05x=28500 | | -13+1=-4(x+8) | | 4x−3=29 | | 39+56x=39+7x | | 4+17=-3(6x-7) | | 7(x-3)=-(12x+16) | | -11+27=-4(x+2) |